If the units of mass length and time are doubled then what happens to the unit of relative density , ? Discuss.

Explanation

An irregular solid when immersed in water displaces `(3)/(4) ` th litre of water . The volume of the solid =750 `cm^(3)`
(l 1 litre =1000 `cm^(3)`)
The mass of the displaced water =750 g
When immersed in a given liquid it displaces =600 g, ,
The relative density of the liquid
`=("density of the liquid")/("density of water ")`
`=("mass of liquid of volume "(V)) /("mass of water of same volume"(V)) =(600g)/(750g)`
Relative density =0.8
`:. ` Density of the liquid is 0.8 g `cm^(-3)`
`=0.8 xx 10^(3) kg m^(-3) =800 kg m`