The number of oxygen atoms in 4.4g of `CO_(2)` is

Options

A. `1.2xx10^(23)`
B. `6xx10^(22)`
C. `6xx10^(23)`
D. `12xx10^(23)`

Answer

a

Explanation

44 g of `CO_(2)" contain" = 6.023xx10^(23)`molecules of `CO_(2)`
4.4g of `CO_(2)` will contain = `6.023xx10^(23)/(44)xx4.44`
`=6.023xx10^(22)` molecules of `CO_(2)~
`1molecule of `CO_(2)` contains two oxygen atoms
`6.023xx91^(22)` molecules of `CO_(2)` will contain
`2xx6.023xx10^(22)=1.210^(23)`oxygen atoms