In the reaction, `Fe(OH)_(3)hArrFe_(aq)^(3+)+3OH_(aq)^(-)` if the concentration of `OH^(-)` ions is decreased by `(1)/(4)` times , then the equilibrium concentration of `Fe^(3+)` will increases by

Options

A. 8 times
B. 16 times
C. 64 times
D. 4 times

Answer

c

Explanation

`K_(c) = [x][3x]^(3)`
When concentration of `OH^(-)` oins is decreased by
`(1)/(4)` times , `K_(C)=[x.][(3x)/(4)]^(3)`….(ii)
equating eq (i) and (ii)
`xxx(3x)^(3)=x.((3x))/(4)^(3)`
64x=x.