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The refractive index of water measured b...

The refractive index of water measured by the relation `m = (real \ depth)/ (apparent\ depth) `is found to have values of 1.34, 1.38, 1.32 and 1.36, the mean value of refractive index with percentage error is

A

`1.36 pm 1.48 %`

B

`1.35 pm 0%`

C

`1.36pm 6%`

D

`1.36 pm 0%`

Text Solution

Verified by Experts

The correct Answer is:
A

The mean value of refractive index,
`mu=(1.34+1.38+1.32+1.36)/(4)=1.35`
and
`Deltamu=(|(1.35-1.34)|+|(1.35-1.38)|+|(1.35-1.32)|+|(1.35-13.6)|)/(4)`
`=0.02`
`"Thus "(Deltamu)/(mu)xx100=(0.02)/(1.35)xx100=1.48`
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