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The momentum of an electron in an orbit ...

The momentum of an electron in an orbit is `h//lambda`, where h is a constant and `lambda` is wavelength associated with it. The nuclear magneton of electron of charge e and mass`m_(e)` is given as `mu_(n)=(eh)/(3672 pim_(e))`. The dimension of `mu_(n)` are `(Ararr"current")`

A

`[ML^(2)A]`

B

`[ML^(3)A]`

C

`[L^(2)A]`

D

`[ML^(2)]`

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The correct Answer is:
To find the dimensions of the nuclear magneton \(\mu_n\) of an electron, we will follow these steps: ### Step 1: Understand the given formula The nuclear magneton \(\mu_n\) is given by the formula: \[ \mu_n = \frac{eh}{3672 \pi m_e} \] where: - \(e\) is the charge of the electron, - \(h\) is Planck's constant, - \(m_e\) is the mass of the electron. ### Step 2: Determine the dimensions of each component 1. **Charge (\(e\))**: The dimension of electric charge is given as: \[ [e] = [I][T] = A \cdot s \] where \(A\) is the unit of current (Ampere) and \(s\) is the unit of time. 2. **Planck's constant (\(h\))**: The dimensions of \(h\) can be derived from the relation \(p \lambda = h\), where \(p\) is momentum and \(\lambda\) is wavelength. - Momentum (\(p\)) has dimensions: \[ [p] = [m][v] = M \cdot L \cdot T^{-1} \] - Wavelength (\(\lambda\)) has dimensions: \[ [\lambda] = L \] - Therefore, the dimensions of \(h\) are: \[ [h] = [p][\lambda] = (M \cdot L \cdot T^{-1}) \cdot L = M \cdot L^2 \cdot T^{-1} \] 3. **Mass of the electron (\(m_e\))**: The dimension of mass is simply: \[ [m_e] = M \] ### Step 3: Substitute the dimensions into the formula for \(\mu_n\) Now we can substitute the dimensions into the formula for \(\mu_n\): \[ \mu_n = \frac{[e][h]}{[m_e]} \] Substituting the dimensions we found: \[ [\mu_n] = \frac{(A \cdot s)(M \cdot L^2 \cdot T^{-1})}{M} \] ### Step 4: Simplify the expression When we simplify this expression: \[ [\mu_n] = (A \cdot s)(L^2 \cdot T^{-1}) \] The \(M\) in the numerator and denominator cancels out: \[ [\mu_n] = A \cdot L^2 \cdot T^{-1} \] ### Final Result Thus, the dimensions of the nuclear magneton \(\mu_n\) are: \[ [\mu_n] = L^2 \cdot A \cdot T^{-1} \]

To find the dimensions of the nuclear magneton \(\mu_n\) of an electron, we will follow these steps: ### Step 1: Understand the given formula The nuclear magneton \(\mu_n\) is given by the formula: \[ \mu_n = \frac{eh}{3672 \pi m_e} \] where: ...
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