The group of molecules having identical shape is:

Options

A. `PCl_(5)IF_(5), XeO_(2)F_(2)`
B. `BF_(3),PCl_(3),XeO_(3)`
C. `SF_(4),XeF_(4),C Cl_(4)`
D. `CIF_(3),XeOF_(2),XeF_(3)^(+)`

Answer

D

Explanation

`CIF_(3) to ` Hybridisation `=3+(1)/(2)[7-3]=5(sp^(3)d)`
`XeOF_(2) to` Hybridisation `=3+(1)/(2)[8-4]=5(Sp^(3)d)`
`XeF_(3)^(+) to` Hybridation `=3+(1)/(2)[8-2-1]=5(sp^(3)d)`
All molecules have `sp^(3)` hybridzation and 2 lone pairs. Hence all have identical (T-shape).