The species in which the N-atom is in a state of sp hybridisation is

Options

A. `NO_(3)^(-)`
B. `NO_(2)`
C. `NO_(3)^(+)`
D. `NO_(2)^(-)`

Answer

C

Explanation

Hybridizatio `(H)=(1)/(2)`. [ no. of valence electrons of central +no. of Movement atoms attached to it +(-ve charge if any)- (+ve charge if any)]
`NO_(2)^(+)=(1)/(2)[5+0+0-1]=2`i.e., sp hybridisation
`NO_(2)^(-)=(1)/(2)[5+2+1-0]=3` I.e., `ps^(2)` hybridisation
`NO_(3)^(-)=(1)/(2)[5+0+1-0]=3` i.e., `sp^(2)` hybridisation
The lewis structure of NO, shows a bent molecular geometry with trigonal planar electron pair geometry Door hence the hybridization will be `sp^(2)`