Bond angle between two hybrid orbitals is `105^@` Percentage of s-orbital character of hybrid orbital is between

Options

A. 50-55%
B. 9-12%
C. 22-23%
D. 11-12%

Answer

C

Explanation

s-character `prop` bond angle
For 25% s character (as in `sp^(3)` hybrid orbital), bond angle is `109,5^(@)`, for 33.3% s character (as in `sp^(2)` hybrid orbital), bond angle is `120^(@)` and for 50% s chal.acter (as in sp hybrid orbital), bond angle is `180^(@)`
Similarly, when the bond angle decreases below `109.50^(@)` the s-character will decrease accordingly.
Decreasing in angle = `120^(@) -109.5^(@) = 10.5^(@)`
Decrease in s-character = 33.3--25= 8.3 <
Actual decrease in bond angle `= 109.50^(@) - 105^(@) = 4.5^(@)`
Expected decrease in s-character `=(8.3)/(10.5)xx4.5=3.56%`
Thus, the s-character should decrease by about 3.56% i.e.,s-character