The group of molecules having identical shape is:

Options

A. `PCl_(5),IF_(5),XeO_(2)F_(2)`
B. `BF_(3),PCl_(3),XeO_(3)`
C. `SF_(4)XeF_(4)C Cl_(4)`
D. `ClF_(3),XeOF_(2),XeF_(3)^(+)`

Answer

D

Explanation

`CIF_(3) to` Hybridisation `=3+(1)/(7)[7-3]=5(sp^(3)d)`
`XeOF_(2) to` Hybridisation `=3+(1)/(2)[8-2]=5(sp^(3)d)`
`XeF_(3)^(+) to` Hybridisation `=3+(1)/(8)[8-3-1]=5(sp^(3) d)`
All molecules have spd hybridization and 2 lone pairs. Hence all have identical (T-shape)