A particle has a charge of `+1.5 mu C` and moves from point A to point B, a distance of 0.20 m. The particle experiences a constant electric force, and its motion is along the line of action of the force. The difference between the particle's electric potential energy at A and B is `EPE_(A) - EPE_(B)=+9.0 xx 10^(-4)` J. Find the magnitude and direction of the electric force that acts on the particle.

Options

A. `3.0 xx 10^(-3)` N, from A toward B
B. `4.5 xx 10^(-3)` N, from A toward B
C. `3.0 xx 10^(-3)` N, from B toward A
D. `4.5 xx 10^(-3)` N, from B toward A

Answer

B