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The acceleration of a sphere falling thr...

The acceleration of a sphere falling through a liquid is `(30 -3v) cm//s^(2)` where v is its speed in cm/s . The maximum possible velocity of the sphere and the time when it is achieved are

A

10 cm /s after 10 second

B

10 cm/s instantly

C

10 cm/s , will never be achieved

D

30 cm/s , after 30 second

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To solve the problem, we need to determine the maximum possible velocity of a sphere falling through a liquid, given its acceleration as \( a = 30 - 3v \) cm/s², where \( v \) is the velocity in cm/s. We also need to find the time when this maximum velocity is achieved. ### Step-by-step Solution: 1. **Understanding the Acceleration**: The acceleration of the sphere is given by: \[ a = 30 - 3v \] We know that acceleration can also be expressed as the change in velocity with respect to time: \[ a = \frac{dv}{dt} \] Therefore, we can equate the two expressions: \[ \frac{dv}{dt} = 30 - 3v \] 2. **Rearranging the Equation**: We can rearrange the equation to isolate \( dv \) and \( dt \): \[ \frac{dv}{30 - 3v} = dt \] 3. **Integrating Both Sides**: We will integrate both sides. The left side requires a substitution. We can factor out the constant: \[ \frac{1}{3} \int \frac{dv}{10 - v} = \int dt \] Integrating gives: \[ -\frac{1}{3} \ln |10 - v| = t + C \] where \( C \) is the constant of integration. 4. **Solving for \( v \)**: Rearranging the equation to solve for \( v \): \[ \ln |10 - v| = -3t - 3C \] Exponentiating both sides: \[ |10 - v| = e^{-3t - 3C} \] Let \( K = e^{-3C} \), then: \[ 10 - v = \frac{K}{e^{3t}} \] Thus: \[ v = 10 - \frac{K}{e^{3t}} \] 5. **Finding Maximum Velocity**: The maximum velocity occurs when the acceleration is zero: \[ 30 - 3v = 0 \] Solving for \( v \): \[ 3v = 30 \implies v = 10 \text{ cm/s} \] 6. **Determining Time for Maximum Velocity**: To find the time when this maximum velocity is achieved, we need to analyze the equation: \[ 10 - v = \frac{K}{e^{3t}} \] When \( v = 10 \): \[ 10 - 10 = \frac{K}{e^{3t}} \implies 0 = \frac{K}{e^{3t}} \] Since \( K \) is a constant, this implies that \( K \) must be zero for this equation to hold true, which means that the maximum velocity of 10 cm/s is never actually achieved in finite time. ### Conclusion: - The maximum possible velocity of the sphere is \( 10 \) cm/s. - This maximum velocity is never actually achieved in finite time.
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