The solution of the primitive integral equation `(x^2+y^2)dy=x ydx` is `y=y(x)dot` If `y(1)=1` and `y(x_0)=e ,` then `x_0` is (a) `( b ) (c)2sqrt(( d ) (e)(( f ) (g) (h) e^(( i )2( j ))( k )-1( l ))( m ))( n ) (o)` (p) (b) `( q ) (r)2sqrt(( s ) (t)(( u ) (v) (w) e^(( x )2( y ))( z )+1( a a ))( b b ))( c c ) (dd)` (ee) (c) `( d ) (e)sqrt(( f )3( g ))( h )e (i)` (j) (d) `( k ) (l)sqrt(( m ) (n) (o)(( p ) (q) e^(( r )2( s ))( t )+1)/( u )2( v ) (w) (x))( y ) (z)` (aa)

Options

A. `sqrt(2(e^(2)-1))`
B. `sqrt(2(e^(2) + 1))`
C. `sqrt(3)e `
D. `sqrt((e^(2) + 1)/(2))`

Answer

C