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The area of the smaller segment cut off ...

The area of the smaller segment cut off from the circle `x^(2)+y^(2)=9` by x = 1 is

A

`(1)/(9)(9sec^(-1)3-sqrt(8))` sq unit

B

`(9sec^(-1)3-sqrt(8))` sq unit

C

`(sqrt(8)-9sec^(-1)3)` sq unit

D

None of the above

Text Solution

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The correct Answer is:
B
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Knowledge Check

  • The area of smaller segment cut-off from the circle x^2+y^2=9" by "x=1 is

    A
    `1/2(9sec^(-1)3-sqrtx)`
    B
    `sec^(-1)3-sqrt8`
    C
    `sqrt8-9sec^(-1)3`
    D
    None of these

  • The area of the smaller part of the circle x^(2)+y^(2)=2 cut off by the line x=1 is

    A
    `(pi)/(2)` sq. units
    B
    `((pi)/(2)-1)` sq. units
    C
    `((pi)/(2)+1)` sq. units
    D
    `((pi)/(2)-(1)/(2))` sq. units

  • The area of the smaller region bounded by the circle x^(2) + y^(2) =1 and the lines |y| = x +1 is

    A
    `(pi-2)//4`
    B
    `(pi-2)//2`
    C
    `(pi+2)//2`
    D
    None of these

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