Home
Class 12
MATHS
Which of the following is not the area o...

Which of the following is not the area of the region bounded by `y= e^(x)` and x=0 and y= e?

A

e-1

B

`int_1^(e)In (e+1-y)dy`

C

`e-int_0^(1)e^(x)dx`

D

`int_0^(e)In y dy`

Text Solution

AI Generated Solution

The correct Answer is:
To find the area of the region bounded by the curve \( y = e^x \), the line \( x = 0 \), and the line \( y = e \), we will follow these steps: ### Step 1: Identify the points of intersection We need to find the points where the curve \( y = e^x \) intersects the line \( y = e \). Setting \( e^x = e \), we can solve for \( x \): \[ e^x = e \implies x = 1 \] Thus, the points of intersection are \( (0, 1) \) and \( (1, e) \). ### Step 2: Set up the integral for the area The area \( A \) can be calculated using the integral of the function \( y = e^x \) from \( x = 0 \) to \( x = 1 \): \[ A = \int_{0}^{1} e^x \, dx \] ### Step 3: Evaluate the integral To evaluate the integral, we find the antiderivative of \( e^x \): \[ \int e^x \, dx = e^x + C \] Now we can evaluate the definite integral: \[ A = \left[ e^x \right]_{0}^{1} = e^1 - e^0 = e - 1 \] ### Step 4: Determine the area bounded by the given lines The area we are interested in is bounded by \( y = e^x \), \( x = 0 \), and \( y = e \). The area can also be calculated using the horizontal strip method, which involves integrating with respect to \( y \). ### Step 5: Change the variable To use the horizontal strip method, we need to express \( x \) in terms of \( y \): \[ y = e^x \implies x = \ln(y) \] ### Step 6: Set up the new integral The area can now be expressed as: \[ A = \int_{1}^{e} \ln(y) \, dy \] ### Step 7: Evaluate the new integral Using integration by parts, where \( u = \ln(y) \) and \( dv = dy \): \[ du = \frac{1}{y} \, dy, \quad v = y \] Applying integration by parts: \[ \int \ln(y) \, dy = y \ln(y) - \int y \cdot \frac{1}{y} \, dy = y \ln(y) - y + C \] Now we evaluate the definite integral: \[ A = \left[ y \ln(y) - y \right]_{1}^{e} \] Calculating it: \[ = \left[ e \cdot 1 - e \right] - \left[ 1 \cdot 0 - 1 \right] = (e - e) - (0 - 1) = 1 \] ### Conclusion The area of the region bounded by the specified curves is \( 1 \).
Promotional Banner

Topper's Solved these Questions

  • APPLICATION OF INTEGRALS

    DISHA PUBLICATION|Exercise EXERCISE-2: CONCEPT BUILDER|30 Videos
  • APPLICATION OF INTEGRALS

    DISHA PUBLICATION|Exercise EXERCISE-2: CONCEPT BUILDER|30 Videos
  • APPLICATION OF DERIVATIVES

    DISHA PUBLICATION|Exercise EXERCISE - 2|30 Videos
  • BINOMIAL THEOREM

    DISHA PUBLICATION|Exercise EXERCISE-2 (CONCEPT APPLICATOR)|30 Videos

Similar Questions

Explore conceptually related problems

The area of the region bounded by y=|x-1| and y=1 is

Find the area of the region bounded by y=sqrt(x) and y=x.

The area of the region bounded by the curve y=e^(x) and lines x=0 and y=e is

The area of the region bounded by y^(2)=x and y = |x| is

Find the area of the region bounded by y=x^2+1, y=x, x=0 and y=2 .

The area of the region bounded by y=x^(2) and y=-x^(2)+2 is

Find the area of the region bounded by y=-1,y=2,x=y^(3) and x=0

The area of the region bonded by y=e^(x),y=e^(-x),x=0 and x = 1 is

DISHA PUBLICATION-APPLICATION OF INTEGRALS-EXERCISE-1: CONCEPT BUILDER (TOPICWISE)
  1. The figure shows a DeltaAOB and the parabola y = x^(2). The ratio of t...

    Text Solution

    |

  2. If the area enclosed by y^2 = 4ax and the line y=ax is 1/3 sq.units, t...

    Text Solution

    |

  3. Which of the following is not the area of the region bounded by y= e^(...

    Text Solution

    |

  4. Find the area of the region bounded by: the parabola y=x^2 and the li...

    Text Solution

    |

  5. The area above the x-axis enclosed by the curves x^(2)-y^(2) = 0 and x...

    Text Solution

    |

  6. Area bounded by the parabola y = x^(2) - 2x + 3 and tangents drawn to ...

    Text Solution

    |

  7. The area between the curves y= x^(2) and y = (2)/(1 + x^(2)) is equal ...

    Text Solution

    |

  8. If the area enclosed by y^(2) = 4ax and the line y=ax is (1)/(3) sq. u...

    Text Solution

    |

  9. The area of the region bounded by the parabola (y-2)^(2) = x- 1, the t...

    Text Solution

    |

  10. Find the area lying in the first quadrant and bounded by the curve y=x...

    Text Solution

    |

  11. Area bounded by the circle x^(2) + y^(2)= 1 and the curve |x| + |y|=1 ...

    Text Solution

    |

  12. A O B is the positive quadrant of the ellipse (x^2)/(a^2)+(y^2)/(b^...

    Text Solution

    |

  13. Find the area enclosed between the curves: y = loge (x + e) , x = loge...

    Text Solution

    |

  14. Find the area bounded by the curves x^2+y^2=25 ,4y=|4-x^2|, and x=0 ab...

    Text Solution

    |

  15. The area bounded by the curves y=x e^x ,y=x e^(-x) and the line x=1 is...

    Text Solution

    |

  16. Using the method of integration find the area of the triangle ABC, ...

    Text Solution

    |

  17. If y=f(x) makes positive intercepts of 2 and 1 unit on x and y-coordin...

    Text Solution

    |

  18. The parabolas y^(2)=4x and x^(2)=4y divide the square region bounded b...

    Text Solution

    |

  19. The area bounded by the curve y^(2)(a^(2)+ x^(2))= x^(2)(a^(2)- x^(2...

    Text Solution

    |

  20. Prove that area common to ellipse (x^2)/(a^2)+(y^2)/(b^2)=1 and its au...

    Text Solution

    |