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If C(1) equiv y = 1/(1+x^(2)) and C(2) e...

If `C_(1) equiv y = 1/(1+x^(2)) and C_(2) equiv y =x^(2) / 2` be two curve lying in XY plane. Then

A

area bounded by `y= (1)/(1+x^(2))` and y=0 is `(pi)/(2)`

B

area bounded by `c_(1)` and `c_(2)` is `(pi)/(2)-1`

C

area bounded by `c_(1)` and `c_(2)` is `1 -(pi)/(2)`

D

area bounded by curve `y = (1)/(1+x^(2))` and x-axis is `(pi)/(2)` ?

Text Solution

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The correct Answer is:
B
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