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If 3A rarr 2B, then the rate of reaction...

If `3A rarr 2B`, then the rate of reaction of `+ (dB)/(d t)` is equal to

A

`-(3)/(2)(d[A])/(dt)`

B

`-(2)/(3)(d[A])/(dt)`

C

`-(1)/(3)(d[A])/(dt)`

D

`+2(d[A])/(dt)`

Text Solution

Verified by Experts

The correct Answer is:
B
`3A to 2B`
Rate of appearance of B is equal to rate of disappearance of A.
`(1)/(2)(d[B])/(dt)=-(1)/(3)(d[A])/(dt)implies (d[B])/(dt)=-(2)/(3)(d[A])/(dt)`
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