The magnetic field of a cylindrical magnet that has a poleface diameter of 3.3 cm can be varied sinusoidally between 29.6 T and 31.2 T at a frequency of 15 Hz. (The current in a wire wrapped around a permanent magnet is varied to give this variation in the net field.) At a radial distance of 1.6 cm, what is the amplitude of the electric field induced by the variation?

Explanation

To solve the problem, we will follow these steps:

### Step 1: Determine the parameters of the magnetic field
- The magnetic field varies between \( B_{\text{min}} = 29.6 \, \text{T} \) and \( B_{\text{max}} = 31.2 \, \text{T} \).
- The amplitude of the magnetic field variation \( B_A \) is calculated as:
\[ B_A = \frac{B_{\text{max}} - B_{\text{min}}}{2} = \frac{31.2 \, \text{T} - 29.6 \, \text{T}}{2} = 0.8 \, \text{T} \]
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