The current in an RL circuit drops from 2.30 A to 3.40 mA in 0.025 s following removal of the battery from the circuit. If L is 10 H, find the resistance R in the circuit.

Explanation

To solve the problem of finding the resistance \( R \) in the RL circuit, we will follow these steps:

### Step 1: Identify the given values
- Initial current \( I_0 = 2.30 \, \text{A} \)
- Final current \( I = 3.40 \, \text{mA} = 3.40 \times 10^{-3} \, \text{A} \)
- Time \( t = 0.025 \, \text{s} \)
- Inductance \( L = 10 \, \text{H} \)

...