A battery is connected to a series RL circuit at time t = 0. At what multiple of `tau_(L)` will the current be 1.00% less than its equilibrium value?

Explanation

To solve the problem, we need to determine the time \( t \) at which the current \( I \) in an RL circuit is 1% less than its maximum (equilibrium) value \( I_{\text{max}} \).

### Step-by-Step Solution:

1. **Understand the Current Equation**:
The current \( I(t) \) in an RL circuit as a function of time is given by:
\[
I(t) = I_{\text{max}} \left(1 - e^{-\frac{t}{\tau_L}}\right)
...