A loop antenna of area 2.00 `cm^(2)` and resistance 5.21 `μOmega`. is perpendicular to a uniform magnetic field of magnitude 17.0 μT. The field magnitude drops to zero in 2.96 ms. How much thermal energy is produced in the loop by the change in field?

Explanation

To solve the problem of how much thermal energy is produced in the loop by the change in the magnetic field, we will follow these steps:

### Step 1: Identify the given values
- Area of the loop, \( A = 2.00 \, \text{cm}^2 = 2.00 \times 10^{-4} \, \text{m}^2 \)
- Resistance of the loop, \( R = 5.21 \, \mu\Omega = 5.21 \times 10^{-6} \, \Omega \)
- Initial magnetic field, \( B_1 = 17.0 \, \mu T = 17.0 \times 10^{-6} \, T \)
- Final magnetic field, \( B_2 = 0 \, T \)
- Time duration for the change, \( t = 2.96 \, ms = 2.96 \times 10^{-3} \, s \)
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