One hundred turns of (insulated) copper wire are wrapped around a wooden cylindrical core of cross-sectional area `1.90 xx 10^(-3) m^(2)`. The two ends of the wire are connected to a resistor. The total resistance in the circuit is 9.50 `Omega`. If an externally applied uniform longitudinal magnetic field in the core changes from 1.60 T in one direction to 1.60 T in the opposite direction, how much charge flows through a point in the circuit during the change?

Explanation

To solve the problem, we need to calculate the charge that flows through the circuit when the magnetic field changes. We'll follow these steps:

### Step 1: Calculate the change in magnetic field (ΔB)
The magnetic field changes from +1.6 T to -1.6 T. The total change in magnetic field (ΔB) is calculated as:
\[ \Delta B = B_f - B_i = -1.6 \, \text{T} - (1.6 \, \text{T}) = -3.2 \, \text{T} \]
However, we are interested in the magnitude of the change:
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