A double-slit arrangement produces interference fringes for sodium light (`lambda= 589 nm`) that have an angular separation of `3.50 xx 10^(-3)` rad. For what wavelength would the angular separation be 6.0% greater?

Explanation

To solve the problem, we need to find the new wavelength when the angular separation is increased by 6%. We start with the given data and use the relationship between wavelength, angular separation, and slit separation.

### Step-by-Step Solution:

1. **Understand the Relationship**:
The angular separation \( \theta \) in a double-slit arrangement is given by the formula:
\[
\theta = \frac{\lambda}{d}
...