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A double-slit arrangement produces inter...

A double-slit arrangement produces interference fringes for sodium light (`lambda=589 nm`) that are `0.25^(@)` apart. What is the angular separation if the arrangement is immersed in water (n=1.33)?

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To solve the problem step by step, we will follow the concepts of interference and the effect of the medium on the wavelength of light. ### Step 1: Understand the given information We know: - Wavelength of sodium light in air, \( \lambda_a = 589 \, \text{nm} = 589 \times 10^{-9} \, \text{m} \) - Angular separation in air, \( \beta_a = 0.25^\circ \) - Refractive index of water, \( n = 1.33 \) ...
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A double slit arrangement produces interference fringes for sodium light (lambda = 5890 Å) that are 0.40^(@) apart. What is the angular fringe separation if the entire arrangement is immersed in water?

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Knowledge Check

  • A double slit arrangement produces interference fringes for sodium light (lambda=589nm) that have an angular separation of 3.50xx10^-3 radian. For what wavelength would the angular separation be 10% greater?

    A
    (a) `527nm`
    B
    (b) `648nm`
    C
    (c) `722nm`
    D
    (d) `449nm`

  • A double-slit experiment, arrangement produces interference fringes for sodium light (lambda = 589 nm) that have an angular separation of 3.50 xx 0^(-3) rad . For what wavelength would the angular separation to 10% greater?

    A
    527 nm
    B
    648 nm
    C
    722 nm
    D
    449 nm

  • A double slit arrangement produces fringes for light lambda=5890Å which are 0.2^@ apart. If the whole arrangement is fully dipped in a liquid of mu=4/3 , the angular fringes separation is

    A
    (a) `0.15^@`
    B
    (b) `0.30^@`
    C
    (c) `0.10^@`
    D
    (d) `0.25^@`

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    A double-slit arrangement produces interference fringes for sodium light ( lambda= 589 nm ) that have an angular separation of 3.50 xx 10^(-3) rad. For what wavelength would the angular separation be 6.0% greater?

    In YDSE performed with wavelength lambda = 5890 Å the angular fringe width is 0.40^(@) . What is the angular fringe width if the entire set-up is immersed in water?

    The interference fringes for sodium light (lambda = 5890 Å) in a double slit experiment have an angular width of 0.2^(@) . For what wavelength will width be 10% greater.

    In a Young's double slit experiment, the angular separation of the interference fringes on a distance screen is 0.04A^(0) . The angular separation if the entire apparatus is immersed in a liquid of R.I. 4/3 is 0.0nA^(0) , then what is the value of n ?

    In the Young's double slit experiment with sodium light, the slits are 0.589m apart. The angular separation of the third maximum from the central maximum will be (given lambda=589mm )

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