Light of wavelength 420 nm is incident on a narrow slit. The angle between the first diffraction minimum on one side of the central maximum and the first minimum on the other side is `2.00^(@)`. What is the width of the slit?

Explanation

To find the width of the slit given the wavelength of light and the angle between the first diffraction minima, we can follow these steps:

### Step 1: Understand the Problem
We are given:
- Wavelength of light, \( \lambda = 420 \, \text{nm} = 420 \times 10^{-9} \, \text{m} \)
- Angle between the first diffraction minima on either side of the central maximum, \( \theta = 2.00^\circ \)

### Step 2: Determine the Angle for One Side
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