Home
Class 12
PHYSICS
A particle starts from the origin at tim...

A particle starts from the origin at time t=0 and moves along the positive x-axis. The graph of velocity with respect to time is shown in figure. What is the position (in metre) of the particle at time t=5s?

Text Solution

Verified by Experts

Position of the particle,
S= area under graph (time t=0 to 5s)
`=1/2 xx2x2+2xx2+3xx1=9m`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • CHAPTERWISE NUMERIC /INTEGER ANSWER QUESTIONS

    DISHA PUBLICATION|Exercise CHAPTER -3 (MOTION IN PLANE)|15 Videos

  • CHAPTERWISE NUMERIC /INTEGER ANSWER QUESTIONS

    DISHA PUBLICATION|Exercise CHAPTER -4 (LAWS OF MOTION)|15 Videos

  • CHAPTERWISE NUMERIC /INTEGER ANSWER QUESTIONS

    DISHA PUBLICATION|Exercise CHAPTER 29 : (COMMUNICATION SYSTEMS)|15 Videos

  • ATOMS

    DISHA PUBLICATION|Exercise EXERCISE-2: CONCEPT APPLICATOR|30 Videos

  • COMMUNICATION SYSTEM

    DISHA PUBLICATION|Exercise EXERCISE-2 : Concept Applicator|30 Videos

Similar Questions

Explore conceptually related problems

A particle starts from the origin at time t = 0 and moves along the positive x-axis. The graph of velocity with respect to time is shown in figure. What is the position of the particle at time t = 5s ?

A particle starts from rest at the origin and moves along the positive x direction. Its acceleration a versus position x graph is shown in the figure. The velocity of the particle at x = 6 m is?

Knowledge Check

  • A particle starts from origin and moving along x- axis. Whose v-t graph is as shown . Choose the INCORRECT statement : .

    A
    At point `L` particle is speeding up.
    B
    At point `M`particle is moving in positive `x-`direction.
    C
    At point `N` particle is speeding up.
    D
    At point O particle is rest.

  • The position versus time graph of a particle moving along a straight line is shown. What is the total distance travelled by the particle from t=0s to t=10s?

    A
    2m
    B
    18 m
    C
    26m
    D
    34m

  • A particle starts moving from the origin & moves along positive x-direction. Its rate of change of kinetic energy with time shown on y-axis varies with time t as shown in the graph. If position, velocity acceleration & kinetic energy of the particle at any time t are x,v a & k respectively then which of the option (s) may be correct ?

    A
    B
    C
    D

    • Similar Questions

    Explore conceptually related problems

    A particle starts at the origin and moves out along the positive x-axis for a while then stops and moves back towards the origin. The distance of the particle from the origin at the end of t seconds is given by x(t)=2t^3-9t^2+12t Find (i) the time t_1, when particle stops for the first time. (i)acceleration at time t_2 when the particle stops for the seconds time

    Velocity-time graph of a particle moving in a straight line is shown in figure. Plot the corresponding displacement-time graph of the particle if at time t=0, displacement s=0.

    The velocity -time (v - t) graph of a particle moving in a straight line is shown in figure. The acceleration of the particle at t = 9 is:

    A particle starts from rest x = - 2.25 m and moves along the x - axis with the v - t graph as shown. The time when the particle crosses the origin is :

    v_(x) is the velocity of a particle moving along the x-axis as shown in the figure. If x=2.0m at t=1.0s, what is the position of the particle at t=6.0s ?

    Home
    Profile