Home
Class 12
PHYSICS
A body starts from rest, if the ration o...

A body starts from rest, if the ration of the distance travelled by the body during the 4th and 3rd second is `x/5`. Find the valud of x.

Text Solution

AI Generated Solution

To solve the problem, we need to find the value of \( x \) given that the ratio of the distance traveled by a body during the 4th second to the distance traveled during the 3rd second is \( \frac{x}{5} \). ### Step-by-Step Solution: 1. **Understanding the Formula**: The distance traveled by a body in the \( n \)-th second can be calculated using the formula: \[ d_n = u + \frac{a}{2} \cdot (2n - 1) ...
Promotional Banner

Topper's Solved these Questions

  • CHAPTERWISE NUMERIC /INTEGER ANSWER QUESTIONS

    DISHA PUBLICATION|Exercise CHAPTER -3 (MOTION IN PLANE)|15 Videos
  • CHAPTERWISE NUMERIC /INTEGER ANSWER QUESTIONS

    DISHA PUBLICATION|Exercise CHAPTER -4 (LAWS OF MOTION)|15 Videos
  • CHAPTERWISE NUMERIC /INTEGER ANSWER QUESTIONS

    DISHA PUBLICATION|Exercise CHAPTER 29 : (COMMUNICATION SYSTEMS)|15 Videos
  • ATOMS

    DISHA PUBLICATION|Exercise EXERCISE-2: CONCEPT APPLICATOR|30 Videos
  • COMMUNICATION SYSTEM

    DISHA PUBLICATION|Exercise EXERCISE-2 : Concept Applicator|30 Videos

Similar Questions

Explore conceptually related problems

A body starts from rest, what is the ratio of the distance travelled by the body during the 4th and 3rd s?

A body starts from rest. What is the retio of the distance traveled by the body during the 4^(th) and 3^(rd) seconds

A body starts from rest with a uniform acceleration ‘a'. Find the distance covered by the body in nth second.

A body starting from rest has an acceleration of 4ms^(-2) . Calculate distnce travelled by it in 5th second.

In the given v-t graph the distance travelled by the body in 5 seconds will be

A body starting from rest has an acceleration of 5m//s^(2) . Calculate the distance travelled by it in 4^(th) second.

A body starting from rest moves with constant acceleration. The ratio of distance covered by the body during the 5th second to that covered in 5 seconds is

A body starting from rest and has uniform acceleration 8 m//s^(2) . The distance travelled by it in 5^(th) second will be

A body starting from rest moves with constant acceleration. The ratio of distance covered by the body during the 5th sec to that covered in 5 sec is