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A body of mass 3 kg is under a constant ...

A body of mass `3 kg` is under a constant force which causes a displacement `s` metre in it, given by the relation `s=(1)/(3)t^(2)`, where `t` is in seconds. Work done by the force in 2 seconds is

Text Solution

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Acceleration `=(d^(2)s)/(dt^(2))=2tms^(2)`
`w=int_(0)^(2)ma.ds`
`=int_(0)^(2)3xx2txxt^(2)dt`
Solving we get
`w=24J`
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