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A metal plate of area 1 xx 10^(-4) m^(2)...

A metal plate of area `1 xx 10^(-4) m^(2)` is illuminated by a radiation of intensity `16m W//m^(2)`. The work function of the metal is 5eV. The energy of the incident photons is 10eV. The energy of the incident photons is 10eV and 10% of it produces photo electrons. The number of emitted photo electrons per second their maximum energy, respectively, will be : `[1 eV = 1.6 xx 10^(-19)J]`

Text Solution

Verified by Experts

Using intensity `I=(nE)/(At)`
n= no. of photoelectrons
`implies16xx10^(-3)=(n/t)xx(10xx1.6xx10^(-19))/(10^(-4))` or `n/t =10^(12)`
So effective number of photoelectrons ejected per unit time `=10^(12)xx10//100=10^(11)`
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