Home
Class 12
PHYSICS
The stopping potential V(0) (in volt ) ...

The stopping potential `V_(0)` (in volt ) as a function of frequeny (v) for a sodium emitter, is shown in the figure.
The work functio (in eV) of sodium, from the data plotted in the figure will be
(Given Plank's constant `(h)=6.63xx10^(-34)` Js, electron charge `e=1.6xx10^(-19)C`)

Text Solution

Verified by Experts

`f_(0)=4xx10^(14)`Hz ,
`W_(0)=hf_(0)=6.63xx10^(-34)xx(4xx10^(14))J`
`=((6.63xx10^(-34))xx(4xx10^(14)))/(1.6xx10^(-19))`
`=1.66eV`
Promotional Banner

Topper's Solved these Questions

  • CHAPTERWISE NUMERIC /INTEGER ANSWER QUESTIONS

    DISHA PUBLICATION|Exercise CHAPTER 26 : (ATOMS)|15 Videos
  • CHAPTERWISE NUMERIC /INTEGER ANSWER QUESTIONS

    DISHA PUBLICATION|Exercise CHAPTER 27 : (NUCLEI)|15 Videos
  • CHAPTERWISE NUMERIC /INTEGER ANSWER QUESTIONS

    DISHA PUBLICATION|Exercise CHAPTER 24 : (WAVE OPTICS)|15 Videos
  • ATOMS

    DISHA PUBLICATION|Exercise EXERCISE-2: CONCEPT APPLICATOR|30 Videos
  • COMMUNICATION SYSTEM

    DISHA PUBLICATION|Exercise EXERCISE-2 : Concept Applicator|30 Videos

Similar Questions

Explore conceptually related problems

The stopping potential V_(0) (in volt) as a function of frequency (v) for a sodium emitter, is shown in the figure. The work function of sodium, from the data plotted in the figure, will be: (Given : Planck’s constant) (h) = 6.63 xx10^(-34)Js" electron charge "e=1.6xx10^(-19)C )

The wavelength of th first spectral line of sodium 5896 Å . The fisrt excitation potential of sodium atomm will be (Planck's constant h=6.63xx10^(-34) J-s)

The momentum of a photon of de Broglie wavelength 5000Å is …………… . [Plank's constant =6.63xx10^(-34)J.s ]

Calculate the speed of the electron in the first Bohr orbit given that h=6.6xx10^(-34) Js, m=9.11xx10^(-31) kg and e=1.603xx10^(-19) C .

If the work function of a and is 3 eV, calculate the threshold wavelength of that metal. (Velocity of light =3xx10^(8)m//s Planck's constant= 6.63xx10^(-34)J-s,1eV=1.6xx10^(-19) )

The electric field of certain radiation is given by the equation E = 200 {sin (4pi xx 10^10)t + sin(4pi xx 10^15)t} falls in a metal surface having work function 2.0 eV. The maximum kinetic energy 2.0 eV. The maximum kinetic energy (in eV) of the photoelectrons is [Plank's constant (h) = 6.63 xx 10^(-34)Js and electron charge e = 1.6 xx 10^(-19)C]

Calculate the wavelength of light incident on a material of work function 2.0 eV if the stopping potential is 1.0 V . Given h = 6.625 xx10^(-34) Js and mass of electron =9.1xx10^(-31) kg