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A hydrogen atom in its ground state is i...

A hydrogen atom in its ground state is irradiated by light of wavelength `970Å` Taking `hc//e = 1.237 xx 10^(-6)`eV m and the ground state energy of hydrogen atom as ` - 13.6 eV` the number of lines present in the emmission spectrum is

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`E=(hc)/(lamda)=(1.237xx10^(-6))/(970xx10^(-10))eV=12.75eV`
`:.` The energy of electron after absorbing this photon
`=-13.6+12.75=-0.85eV`
This corresponds to n=4
Number of spectral line `=(n(n-1))/2=(4(4-1))/2=6`
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