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e^(3x)cos 2x...

`e^(3x)cos 2x`

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To differentiate the function \( y = e^{3x} \cos(2x) \), we will use the product rule of differentiation. The product rule states that if you have two functions \( u(x) \) and \( v(x) \), then the derivative of their product is given by: \[ \frac{d}{dx}(u \cdot v) = u'v + uv' \] In our case, let: - \( u = e^{3x} \) ...
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