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log("cosec x"-cot x)...

`log("cosec x"-cot x)`

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To differentiate the function \( y = \log(\csc x - \cot x) \), we will follow these steps: ### Step 1: Differentiate the function using the chain rule We start with the function: \[ y = \log(\csc x - \cot x) \] Using the chain rule, the derivative \( \frac{dy}{dx} \) is given by: ...
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Knowledge Check

  • If y=log (cosec x -cotx) ,then (dy)/(dx)

    A
    ` -cosec x `
    B
    ` cosec x `
    C
    ` -(cosec x -cotx ) `
    D
    ` cosec x -cotx `
  • If y=tan^(-1) ("cosec x"-cot x),"then " dy/dx=

    A
    ` 1`
    B
    ` -1`
    C
    ` (1)/(2)`
    D
    ` (-1)/(2)`
  • If y=cot^(-1) ("cosec x"+cot x),"then " dy/dx=

    A
    `-1`
    B
    ` 1`
    C
    ` (-1)/(2)`
    D
    ` (1)/(2) `
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