An edge of a variable cube is increasing at the rate of 5 cm/s. How fast is the volume of the cube increasing when the edge is 10 cm long ?

Answer

`1500 cm^(3)//s`

Explanation

`V = x^(3) rArr (dV)/(dt) = 3x^(2).(dx)/(dt) = [3 xx (10)^(2) xx 5] cm^(3)//s`