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Evaluate : int sin^(-1) (cosx) dx....

Evaluate : `int sin^(-1) (cosx) dx`.

Text Solution

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`int sin^(-1)(cosx) dx =intsin^(-1){sin(pi/2-x)}dx`
`= int(pi/2-x)dx = pi/2.intdx - intxdx = (nx)/(2) - (x^(2))/(2) +C`.
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