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(i) int(2x-5x) (3+2x) (1-x) dx, (ii) int...

(i) `int(2x-5x) (3+2x) (1-x) dx`, (ii) `int sqrt(x) (ax^(2) + bx + c) dx`
(iii) `int (sqrtx - 3sqrt(x^(4)) + 7/(3sqrt(x^(2))) - 6e^(x) + 1) dx`

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Let's solve the given integrals step by step. ### (i) Integral: \(\int (2x - 5x)(3 + 2x)(1 - x) \, dx\) 1. **Simplify the expression inside the integral:** \[ 2x - 5x = -3x \] So, we rewrite the integral: \[ \int (-3x)(3 + 2x)(1 - x) \, dx \] 2. **Expand the expression:** \[ (-3x)(3 + 2x)(1 - x) = -3x[(3 + 2x)(1 - x)] \] Now, expand \((3 + 2x)(1 - x)\): \[ = 3(1 - x) + 2x(1 - x) = 3 - 3x + 2x - 2x^2 = 3 - x - 2x^2 \] Thus, \[ -3x(3 - x - 2x^2) = -9x + 3x^2 + 6x^3 \] 3. **Rewrite the integral:** \[ \int (-9x + 3x^2 + 6x^3) \, dx \] 4. **Integrate term by term:** \[ = \int -9x \, dx + \int 3x^2 \, dx + \int 6x^3 \, dx \] \[ = -\frac{9}{2}x^2 + x^3 + \frac{6}{4}x^4 + C \] \[ = -\frac{9}{2}x^2 + x^3 + \frac{3}{2}x^4 + C \] ### (ii) Integral: \(\int \sqrt{x}(ax^2 + bx + c) \, dx\) 1. **Rewrite \(\sqrt{x}\) as \(x^{1/2}\):** \[ \int x^{1/2}(ax^2 + bx + c) \, dx \] 2. **Distribute \(\sqrt{x}\):** \[ = \int (ax^{5/2} + bx^{3/2} + cx^{1/2}) \, dx \] 3. **Integrate term by term:** \[ = a \int x^{5/2} \, dx + b \int x^{3/2} \, dx + c \int x^{1/2} \, dx \] \[ = a \cdot \frac{x^{7/2}}{7/2} + b \cdot \frac{x^{5/2}}{5/2} + c \cdot \frac{x^{3/2}}{3/2} + C \] \[ = \frac{2a}{7} x^{7/2} + \frac{2b}{5} x^{5/2} + \frac{2c}{3} x^{3/2} + C \] ### (iii) Integral: \(\int (\sqrt{x} - 3\sqrt{x^4} + \frac{7}{3\sqrt{x^2}} - 6e^x + 1) \, dx\) 1. **Rewrite the terms:** \[ = \int (x^{1/2} - 3x^2 + \frac{7}{3}x^{-1} - 6e^x + 1) \, dx \] 2. **Integrate term by term:** \[ = \int x^{1/2} \, dx - 3 \int x^2 \, dx + \frac{7}{3} \int x^{-1} \, dx - 6 \int e^x \, dx + \int 1 \, dx \] \[ = \frac{x^{3/2}}{3/2} - 3 \cdot \frac{x^3}{3} + \frac{7}{3} \ln|x| - 6e^x + x + C \] \[ = \frac{2}{3} x^{3/2} - x^3 + \frac{7}{3} \ln|x| - 6e^x + x + C \] ### Summary of Results: 1. \(\int (2x - 5x)(3 + 2x)(1 - x) \, dx = -\frac{9}{2}x^2 + x^3 + \frac{3}{2}x^4 + C\) 2. \(\int \sqrt{x}(ax^2 + bx + c) \, dx = \frac{2a}{7} x^{7/2} + \frac{2b}{5} x^{5/2} + \frac{2c}{3} x^{3/2} + C\) 3. \(\int (\sqrt{x} - 3\sqrt{x^4} + \frac{7}{3\sqrt{x^2}} - 6e^x + 1) \, dx = \frac{2}{3} x^{3/2} - x^3 + \frac{7}{3} \ln|x| - 6e^x + x + C\)
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RS AGGARWAL-INDEFINITE INTEGRAL -Exercise 12
  1. Evaluated : (i) intx^(7)d, (ii) intx^(-7)dx , (iii) intx^(-1)dx (...

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  2. (i) int(6x^(5) - 2/(x^(4)) - 7x + 3/x - 5 + 4e^(x) + 7^(x))dx (ii) i...

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  3. (i) int(2x-5x) (3+2x) (1-x) dx, (ii) int sqrt(x) (ax^(2) + bx + c) dx ...

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  4. (i) int(x^(2) - 1/(x^(2)))^(3) dx , (ii) int(sqrt(x) -1/(sqrt(x))) dx ...

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  5. int[1+(1)/((1+x^(2)))-(2)/(sqrt(1-x^(2)))+(5)/(x sqrt(x^(2)-1))+a^(x)]...

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  6. (i) int((x^(2) - 1)/(x^(2) + 1))dx , (ii) int ((x^(6)- 1)/(x^(2) + 1))...

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  7. int(9sinx - 7 cosx - 6/(cos^(2)x) + 2/(sin^(2)x)+ cot^(2)x) dx

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  8. int((cotx)/(sinx) - tan^(2)x -(tanx)/(cosx) + 2/(cosx)) dx

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  9. (i) intsecx (secx +tanx) dx (ii) intcosec x(cosecx + cot x)dx

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  10. (i)int (tanx + cot x)^(2) dx , (ii) int((1+2 sinx)/(cos^(2)x))dx , (i...

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  11. (i) int(tanx)/((sec x +tanx))dx , (ii) int(1)/((1-sinx))dx

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  12. (i) int (tanx)/((secx + tanx))dx ,(ii) int(cosecx)/((cosecx- cotx))dx

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  13. (i) int (cosx)/(1+cosx)dx , (ii) int (sinx)/((1-sinx))dx

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  14. (i) int sqrt(1+cos2x) dx , (ii) intsqrt(1-cos2x)dx

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  15. (i) int(1)/((1+cos2x))dx , (ii) int (1)/((1-cos2x)) dx

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  16. int sqrt(1+sin2x)dx

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  17. int (sin^3x+cos^3x)/(sin^2x*cos^2x)dx

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  18. int tan^(-1) ((sin2x)/(1+cos 2x))dx

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  19. intcos^(-1) ((1+tan^(2)x)/(1+tan^(2) x)) dx

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  20. int cos^(-1) (sinx) dx

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