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Evaluate int0^1 (1-x)/(1+x) dx...

Evaluate `int_0^1 (1-x)/(1+x) dx`

A

`(1)/(2)log2`

B

`(2log2+1)`

C

`(2log2-1)`

D

`((1)/(2)log2-1)`

Text Solution

Verified by Experts

On dividing `(-x+1)` by `(x+1)` we get :
`I=int_(0)^(1){-1+(2)/((x+1))}dx=[-x+2log(x+1)]_(0)^(1)=(2log2-1)`.
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