A radioactive sample decays to half of i...

A radioactive sample decays to half of its initial concentration in 6.93 minutes. If it further decays another half in next 6.93 minutes, then the rate constant for the reaction is:

`0.10 "min"^(-1)`

`0.01 "min"^(-1)`

`1.0 "min"^(-1)`

`0.001 "min"^(-1)`

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The correct Answer is:

`k = (0.693)/(t_(1//2)) = (0.693)/(6.93) = 0.10 "min"^(-1)`

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