Home
Class 12
CHEMISTRY
Given that radioactive species decays ac...

Given that radioactive species decays according to the exponential law `N=N_(0) e^(-lambda t)`. The half life of the species is

A

`lamda`

B

No

C

`lamda//ln 2`

D

`ln 2//lamda`

Text Solution

Verified by Experts

The correct Answer is:
D

`t_(1//2) = ln 2//lamda`
Promotional Banner

Topper's Solved these Questions

  • NUCLEAR CHEMISTRY

    ERRORLESS |Exercise Ordinary Thinking (Artificial transmutation )|59 Videos
  • NUCLEAR CHEMISTRY

    ERRORLESS |Exercise Ordinary Thinking (Isotopes-Isotones and Nuclear isomers)|34 Videos
  • NUCLEAR CHEMISTRY

    ERRORLESS |Exercise Ordinary Thinking (Causes of radioactivity and Group displacement law)|66 Videos
  • NITROGEN CONTAINING COMPOUNDS

    ERRORLESS |Exercise JEE (ADVANCED) 2018 MORE THAN ONE CHOICE CORRECT ANSWER|1 Videos
  • ORES, MINERALS AND METALLURGICAL EXTRACTION

    ERRORLESS |Exercise JEE ANSWER TPYE QUESTION (JEE Advanced) 2018) Numeric answer type question|1 Videos

Similar Questions

Explore conceptually related problems

The rate of decay of a radioactive species is given by R_(1) at time t_(1) and R_(2) at later time t_(2) . The mean life of this radioactive species is:

Radioactive decay follows first-order kinetic. The mean life and half-life of nuclear decay process are tau = 1// lambda and t_(1//2) = 0.693//lambda . Therefore are a number of radioactive elements in nature, their abundance is directly proportional to half life. The amount remaining after n half lives of radioactive elements can be calculated using the relation: N = N_(0) ((1)/(2))^(n) The rate of radioactive decay is

A radioactive species undergoes decay for time t where t = 4t_(1//2) . The average life (T) of species can therefore be given by:

The decay constant of a radioactive sample is lambda . The half-life and mean life of the sample respectively are

Radioactive decay follows first-order kinetic. The mean life and half-life of nuclear decay process are tau = 1// lambda and t_(1//2) = 0.693//lambda . Therefore are a number of radioactive elements in nature, their abundance is directly proportional to half life. The amount remaining after n half lives of radioactive elements can be calculated using the relation: N = N_(0) ((1)/(2))^(n) Half life of .^(60)Co is 5.3 years, the time taken for 99.9% decay will be

ERRORLESS -NUCLEAR CHEMISTRY -Ordinary Thinking (Rate of decay and Half - life)
  1. 2 g of a radioactive sample having half-life of 15 days was synthesise...

    Text Solution

    |

  2. If n(t) number of radioatoms are present at time t, the following expr...

    Text Solution

    |

  3. The half-life for decay of .^(14)C " by " beta-emission is 5730 years....

    Text Solution

    |

  4. Rate constant for a reaction is lambda. Average life is representative...

    Text Solution

    |

  5. In which radiation mass number and atomic number will not change ?

    Text Solution

    |

  6. t(1//2) of C^(14) isotope is 5770 years. time after which 72% of isot...

    Text Solution

    |

  7. A radioactive substance takes 20 min to decay 25%. How much time will ...

    Text Solution

    |

  8. What kind of radioactive decay does not lead to the formation of a dau...

    Text Solution

    |

  9. Given that radioactive species decays according to the exponential law...

    Text Solution

    |

  10. A radioactive isotope decays at such a rate that after 192 minutes onl...

    Text Solution

    |

  11. Half - life for radioactive .^(14)C is 5760 years. In how many years 2...

    Text Solution

    |

  12. A certain nuclide has a half-life period of 30 minutes. If a sample co...

    Text Solution

    |

  13. For a reaction, the rate constant is 2.34 s^(-1). The half-life period...

    Text Solution

    |

  14. The half-life of a radionuclide is 69.3 minutes. What is its average l...

    Text Solution

    |

  15. .(11)Na^(24) half-life is 15 hours. On heating it will

    Text Solution

    |

  16. A radioactive isotope has a half-life of 20 days. If 100 g of the subs...

    Text Solution

    |

  17. The decay of a radioactive element follows first order kinetic. Thus, ...

    Text Solution

    |

  18. 1.0 g radioactive sodium on decay becomes 0.25 g in 16 hours. How much...

    Text Solution

    |

  19. The decay constant of Ra^(226) is 1.37xx10^(-11)s^(-1). A sample of Ra...

    Text Solution

    |

  20. The ratio of the amount of two element X and Y at radioactive equilibr...

    Text Solution

    |