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A radioactive isotope decays at such a r...

A radioactive isotope decays at such a rate that after 192 minutes only 1/16 of the original amount remains. The half life of the radioactive isotope is

A

32min

B

48 min

C

12 min

D

24 min

Text Solution

Verified by Experts

The correct Answer is:
B
`(N)/(N_(0)) = ((1)/(2))^((T)/(t_(1//2))), ((1)/(16)) = ((1)/(2))^((192)/(t_(1//2))), ((1)/(2))^(4) = ((1)/(2))^((192)/(t_(1//2)))`
`t_(1//2) = 48` min
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  • A radioactive isotope decays at such a rate that after 96 minutes only (1)/(8)th of the original amount remains. The half-life of this nuclide in minutes is

    A
    12
    B
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    C
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    D
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  • A radioactive isotope decays to such a rate that after 96 min only 1/8th of the original amount remains. The value t_(1//2) of this nuclide is

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    12.0 min
    B
    32.0 min
    C
    24.0 min
    D
    48.0 min

  • A radioactive isotope decays at such a rate that after 96 min, only 1//8th of the original amount remains. The value of t_(1//2) of this nuclide is a. 12 min b. 32 min c. 24 min d. 48 min

    A
    a. 12 min
    B
    b. 32 min
    C
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