A radioactive isotope decays at such a rate that after 192 minutes only 1/16 of the original amount remains. The half life of the radioactive isotope is

Options

A. 32min
B. 48 min
C. 12 min
D. 24 min

Answer

B

Explanation

`(N)/(N_(0)) = ((1)/(2))^((T)/(t_(1//2))), ((1)/(16)) = ((1)/(2))^((192)/(t_(1//2))), ((1)/(2))^(4) = ((1)/(2))^((192)/(t_(1//2)))`
`t_(1//2) = 48` min