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For the reaction C(s) +CO(2)(g) rarr 2CO...

For the reaction `C(s) +CO_(2)(g) rarr 2CO(g), k_(p)=63` atm at 100 K. If at equilibrium `p_(CO)=10p_(CO_(2)) ` then the total pressure of the gases at equilibrium is

A

`6.3` atm

B

`6.93` atm

C

`0.63` atm

D

`69.3` atm

Text Solution

Verified by Experts

The correct Answer is:
B
`C_((s))+CO_(2(g))to2CO_((g))`
Apply low of mass action,
`K_(p)=((P_(CO))^(2))/(P_(CO_(2)))or 63=((10P_(CO_(2)))^(2))/(P_(CO_(2)))`
or `63=(100(P_(CO_(2)))^(2))/(P_(CO_(2)))or 63=100P_(CO_(2))`
`P_(CO_(2))36/100=0.63atm`
`P_(Total)=P_(CO_(2))+P_(CO)=0.63+6.3=6.93 ` atm.
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