0.2 M solution of formic acid is ionized...

`0.2` M solution of formic acid is ionized `3.2%`. Its ionization constant is

`9.6 xx 10^(-3)`

`2.1 xx 10^(-4)`

`1.25 xx 10^(-6)`

`4.8 xx 10^(-5)`

Verified by Experts

The correct Answer is:

`K_(a) = C alpha^(2) = 0.2 xx ((3.2)/(100))^(2) = 2.048 xx 10^(-4) = 2.1 xx 10^(-4)`.

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