If `alpha` is the degree of ionization, C the concentration of a weak electrolyte and `K_(a)` the acid ionization constant , then the correct relationship between `alpha` and C is

Options

A. `alpha^(2) = sqrt((K_(a))/(C))`
B. `alpha^(2) = sqrt((C)/(K_(a))`
C. `alpha = sqrt((K_(a))/(C))`
D. `alpha = sqrt((C)/(K_(a))`

Answer

C

Explanation

According to the Ostwald's dilution formula `alpha^(2) = (K(1- alpha))/(C)`. But for weak electrolytes `alpha` is very small. So that `(1- alpha)` can be neglected. So that `alpha = sqrt((K_(a))/(C))`.