Molar heat of neutralization of NaOH with HCl in comparison to that of KOH with `HNO_(3)` is

Options

A. Less
B. More
C. Equal
D. Depends on pressure

Explanation

To solve the question regarding the molar heat of neutralization of NaOH with HCl compared to that of KOH with HNO3, we will follow these steps:

### Step 1: Understand the Neutralization Reaction
Neutralization reactions involve an acid reacting with a base to produce water and a salt. The general reaction can be represented as:
- For NaOH and HCl:
\[ \text{NaOH} + \text{HCl} \rightarrow \text{NaCl} + \text{H}_2\text{O} \]
- For KOH and HNO3:
\[ \text{KOH} + \text{HNO}_3 \rightarrow \text{KNO}_3 + \text{H}_2\text{O} \]

### Step 2: Identify the Heat of Neutralization
The molar heat of neutralization is the amount of heat released when one mole of water is formed during the neutralization reaction. Both reactions produce one mole of water.

### Step 3: Compare the Reactions
- In both reactions (NaOH with HCl and KOH with HNO3), one mole of water is produced.
- The heat released during the neutralization process is primarily due to the formation of water from the hydrogen ions (H⁺) from the acid and hydroxide ions (OH⁻) from the base.

### Step 4: Conclusion
Since both reactions produce one mole of water and the nature of the acids and bases involved does not affect the amount of heat released significantly, we can conclude that:
- The molar heat of neutralization for NaOH with HCl is approximately equal to that of KOH with HNO3.

Thus, the answer to the question is that the molar heat of neutralization of NaOH with HCl is comparable to that of KOH with HNO3.

### Final Answer
The molar heat of neutralization of NaOH with HCl is equal to that of KOH with HNO3.

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