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Calculate the pOH of solution at 25^(@)C...

Calculate the `pOH` of solution at `25^(@)C` that contains `1xx10^(-10) M` of hydronium ions, i.e., `H_(3)O^(+)`

A

`7.000`

B

`4.000`

C

`9.000`

D

`1.000`

Text Solution

Verified by Experts

The correct Answer is:
B
Given `H_(3)O^(+)` ion concentration `= 1 xx 10^(-10)`
`pH = -log[H^(+)], pH = -log[1 xx 10^(-10)]`,
`pH = + 10 log 10, pH = 10`
We know that, `pH + pOH = 14` ....(i)
Put the value of pH in eq. (i)
`10 + P^(OH) = 14`
`F^(OH) = 4`.
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