100 mL of 0.01 M solution of NaOH is diluted to 1 litre. The pH of resultant solution will be

Options

A. 12
B. 11
C. 2
D. 3

Answer

B

Explanation

100 ml 0.01 M NaOH solution is diluted to `1 dm^(3)` (i.e., 10 times dluted) hence, the resultant solution will be 0.001 M.
`:. [OH^(-)] = 0.001 = 10^(-3)`
`[H^(+)] = (10^(-14))/([OH^(-)]) = (10^(-14))/(10^(-3)) = 10^(-11)`
`because pH = - log[H^(+)] = -log[10^(-11)]`
pH = 11.