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The pH of a 0.1M NH(3) solution (K(b)=1....

The pH of a 0.1M `NH_(3)` solution `(K_(b)=1.8 xx 10^(-5))` is

A

11.13

B

12.5

C

13.42

D

11.55

Text Solution

Verified by Experts

The correct Answer is:
A
`NH_(4)OH hArr NH_(4)^(+) + OH^(-)`
`K_(b) = C alpha^(2) , (1.8 xx 10^(-5))/(.1) = alpha^(2), alpha = 1.34 xx 10^(-3)`
`[OH^(-)] = alpha. C = 1.34 xx 10^(-3) xx .1`
`pOH = log 10(1)/(1.34 xx 10^(-4)) , pOH = 2.87`
`pH = pOH = 14 , pH + 2.87 = 14`
`pH = 14 - 2.87, pH = 11.13`.
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