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0.023 g of sodium metal is reacted with ...

0.023 g of sodium metal is reacted with 100`cm^(3)` of water. The pH of the resulting solution is

A

10

B

11

C

9

D

12

Text Solution

Verified by Experts

The correct Answer is:
D
`M = (0.023 xx 1000)/(23 xx 100) = 0.01 M`
`Na^(+) + oH^(-) NaOH`
`[OH^(-)] = 0.01 M = 10^(-2)M, pOH = -log (10^(-2)) = 2`
`pH + pOH = 14`
`:. pH = 14 - 2 = 12`
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