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Figure shows the stopping potential (V(0...

Figure shows the stopping potential `(V_(0))` for the photo electron vers `((1)/(lambda))` graph, for two metals A and B, `lambda` being the wavelength of incident light.

How is the value of Planck's constant determined from the graph ?

Text Solution

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We know that `V_(0)=(h)/(e ) (v-v_(0))= (hc)/(e ) ((1)/(lambda)-(1)/(lambda_(0)))`.
So `V_(0)- (1)/(lambda)` graph is a straight line graph whose slope has a magnitude of `(hc)/(e )` .
Thus, Planck.s constant `h= (e )/(c )xx ("Slope of " V_(0)-(1)/(lambda)` aph for any photosensitive metal)
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