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The radius of curvature of the path of a...

The radius of curvature of the path of a charged particle moving in a static uniform magnetic field is

A

Directly propotional to the magnitude of the charge on the particle

B

Directly propotional to the magnitude of the liner momentum of the particle

C

Directly proportional to the kinetic energy of the particle

D

Inversely proportional to the magnitude of the magnetic field

Text Solution

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The correct Answer is:
To find the radius of curvature of the path of a charged particle moving in a static uniform magnetic field, we can use the following steps: ### Step-by-Step Solution: 1. **Understand the Motion of Charged Particles in a Magnetic Field**: When a charged particle moves in a magnetic field, it experiences a magnetic force that acts perpendicular to its velocity. This results in circular motion. 2. **Identify the Relevant Formula**: The radius of curvature \( r \) of the path of a charged particle in a magnetic field can be expressed by the formula: \[ r = \frac{mv}{qB} \] where: - \( m \) = mass of the particle - \( v \) = velocity of the particle - \( q \) = charge of the particle - \( B \) = magnetic field strength 3. **Analyze the Proportional Relationships**: - From the formula \( r = \frac{mv}{qB} \): - The radius \( r \) is **directly proportional** to the momentum \( mv \) of the particle. - The radius \( r \) is **inversely proportional** to the charge \( q \) of the particle. - The radius \( r \) is also **inversely proportional** to the magnetic field strength \( B \). 4. **Evaluate the Options**: - **Option A**: "Directly proportional to the magnitude of charge" - This is incorrect as \( r \) is inversely proportional to \( q \). - **Option B**: "Directly proportional to the magnitude of linear momentum of the particle" - This is correct since \( r \) is directly proportional to \( mv \). - **Option C**: "Directly proportional to the kinetic energy of the particle" - This can be evaluated using the relationship \( KE = \frac{p^2}{2m} \). Since \( p = mv \), we can show that \( r \) is also related to kinetic energy. - **Option D**: "Inversely proportional to the magnetic field strength" - This is correct as \( r \) is inversely proportional to \( B \). 5. **Conclusion**: Based on the analysis, the correct options are B, C, and D.
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