The density of silver is 10.5 g/cc and its atomic mass is approximately 108 g . Assume each atom contributes one free electron and calcute the number of free electrons per unit volume for the silver. Resistivity of the silver is `1.6 xx10^(-8) Omega`m.
What potential difference must be applied across the silver wire of length 0.1 m and area of cross section `1mm^2` so that a current of 2A flows through it ? what will be the current density for the wire and drift speed of electrons ?

Explanation

To solve the problem step by step, we can break it down into parts as follows:

### Step 1: Calculate the number of free electrons per unit volume for silver.

1. **Given Data:**
- Density of silver (ρ) = 10.5 g/cc = 10.5 x 10^3 kg/m³ (since 1 g/cc = 1000 kg/m³)
- Atomic mass of silver (M) = 108 g/mol = 0.108 kg/mol
- Avogadro's number (N_A) = 6.022 x 10²³ atoms/mol
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